Integrand size = 26, antiderivative size = 78 \[ \int x^5 \left (a^2+2 a b x^3+b^2 x^6\right )^{5/2} \, dx=-\frac {a \left (a+b x^3\right )^5 \sqrt {a^2+2 a b x^3+b^2 x^6}}{18 b^2}+\frac {\left (a+b x^3\right )^6 \sqrt {a^2+2 a b x^3+b^2 x^6}}{21 b^2} \]
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Time = 0.04 (sec) , antiderivative size = 78, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.115, Rules used = {1369, 272, 45} \[ \int x^5 \left (a^2+2 a b x^3+b^2 x^6\right )^{5/2} \, dx=\frac {\left (a+b x^3\right )^6 \sqrt {a^2+2 a b x^3+b^2 x^6}}{21 b^2}-\frac {a \left (a+b x^3\right )^5 \sqrt {a^2+2 a b x^3+b^2 x^6}}{18 b^2} \]
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Rule 45
Rule 272
Rule 1369
Rubi steps \begin{align*} \text {integral}& = \frac {\sqrt {a^2+2 a b x^3+b^2 x^6} \int x^5 \left (a b+b^2 x^3\right )^5 \, dx}{b^4 \left (a b+b^2 x^3\right )} \\ & = \frac {\sqrt {a^2+2 a b x^3+b^2 x^6} \text {Subst}\left (\int x \left (a b+b^2 x\right )^5 \, dx,x,x^3\right )}{3 b^4 \left (a b+b^2 x^3\right )} \\ & = \frac {\sqrt {a^2+2 a b x^3+b^2 x^6} \text {Subst}\left (\int \left (-\frac {a \left (a b+b^2 x\right )^5}{b}+\frac {\left (a b+b^2 x\right )^6}{b^2}\right ) \, dx,x,x^3\right )}{3 b^4 \left (a b+b^2 x^3\right )} \\ & = -\frac {a \left (a+b x^3\right )^5 \sqrt {a^2+2 a b x^3+b^2 x^6}}{18 b^2}+\frac {\left (a+b x^3\right )^6 \sqrt {a^2+2 a b x^3+b^2 x^6}}{21 b^2} \\ \end{align*}
Time = 0.69 (sec) , antiderivative size = 135, normalized size of antiderivative = 1.73 \[ \int x^5 \left (a^2+2 a b x^3+b^2 x^6\right )^{5/2} \, dx=\frac {x^6 \left (21 a^5+70 a^4 b x^3+105 a^3 b^2 x^6+84 a^2 b^3 x^9+35 a b^4 x^{12}+6 b^5 x^{15}\right ) \left (\sqrt {a^2} b x^3+a \left (\sqrt {a^2}-\sqrt {\left (a+b x^3\right )^2}\right )\right )}{126 \left (-a^2-a b x^3+\sqrt {a^2} \sqrt {\left (a+b x^3\right )^2}\right )} \]
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Result contains higher order function than in optimal. Order 9 vs. order 2.
Time = 0.11 (sec) , antiderivative size = 31, normalized size of antiderivative = 0.40
method | result | size |
pseudoelliptic | \(-\frac {\operatorname {csgn}\left (b \,x^{3}+a \right ) \left (b \,x^{3}+a \right )^{6} \left (-6 b \,x^{3}+a \right )}{126 b^{2}}\) | \(31\) |
gosper | \(\frac {x^{6} \left (6 b^{5} x^{15}+35 a \,b^{4} x^{12}+84 a^{2} b^{3} x^{9}+105 a^{3} b^{2} x^{6}+70 a^{4} b \,x^{3}+21 a^{5}\right ) {\left (\left (b \,x^{3}+a \right )^{2}\right )}^{\frac {5}{2}}}{126 \left (b \,x^{3}+a \right )^{5}}\) | \(80\) |
default | \(\frac {x^{6} \left (6 b^{5} x^{15}+35 a \,b^{4} x^{12}+84 a^{2} b^{3} x^{9}+105 a^{3} b^{2} x^{6}+70 a^{4} b \,x^{3}+21 a^{5}\right ) {\left (\left (b \,x^{3}+a \right )^{2}\right )}^{\frac {5}{2}}}{126 \left (b \,x^{3}+a \right )^{5}}\) | \(80\) |
risch | \(\frac {\sqrt {\left (b \,x^{3}+a \right )^{2}}\, a^{5} x^{6}}{6 b \,x^{3}+6 a}+\frac {5 \sqrt {\left (b \,x^{3}+a \right )^{2}}\, b \,a^{4} x^{9}}{9 \left (b \,x^{3}+a \right )}+\frac {5 \sqrt {\left (b \,x^{3}+a \right )^{2}}\, a^{3} b^{2} x^{12}}{6 \left (b \,x^{3}+a \right )}+\frac {2 \sqrt {\left (b \,x^{3}+a \right )^{2}}\, a^{2} b^{3} x^{15}}{3 \left (b \,x^{3}+a \right )}+\frac {5 \sqrt {\left (b \,x^{3}+a \right )^{2}}\, b^{4} a \,x^{18}}{18 \left (b \,x^{3}+a \right )}+\frac {\sqrt {\left (b \,x^{3}+a \right )^{2}}\, b^{5} x^{21}}{21 b \,x^{3}+21 a}\) | \(178\) |
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Time = 0.25 (sec) , antiderivative size = 57, normalized size of antiderivative = 0.73 \[ \int x^5 \left (a^2+2 a b x^3+b^2 x^6\right )^{5/2} \, dx=\frac {1}{21} \, b^{5} x^{21} + \frac {5}{18} \, a b^{4} x^{18} + \frac {2}{3} \, a^{2} b^{3} x^{15} + \frac {5}{6} \, a^{3} b^{2} x^{12} + \frac {5}{9} \, a^{4} b x^{9} + \frac {1}{6} \, a^{5} x^{6} \]
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\[ \int x^5 \left (a^2+2 a b x^3+b^2 x^6\right )^{5/2} \, dx=\int x^{5} \left (\left (a + b x^{3}\right )^{2}\right )^{\frac {5}{2}}\, dx \]
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Time = 0.21 (sec) , antiderivative size = 83, normalized size of antiderivative = 1.06 \[ \int x^5 \left (a^2+2 a b x^3+b^2 x^6\right )^{5/2} \, dx=-\frac {{\left (b^{2} x^{6} + 2 \, a b x^{3} + a^{2}\right )}^{\frac {5}{2}} a x^{3}}{18 \, b} - \frac {{\left (b^{2} x^{6} + 2 \, a b x^{3} + a^{2}\right )}^{\frac {5}{2}} a^{2}}{18 \, b^{2}} + \frac {{\left (b^{2} x^{6} + 2 \, a b x^{3} + a^{2}\right )}^{\frac {7}{2}}}{21 \, b^{2}} \]
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Time = 0.28 (sec) , antiderivative size = 67, normalized size of antiderivative = 0.86 \[ \int x^5 \left (a^2+2 a b x^3+b^2 x^6\right )^{5/2} \, dx=\frac {1}{126} \, {\left (6 \, b^{5} x^{21} + 35 \, a b^{4} x^{18} + 84 \, a^{2} b^{3} x^{15} + 105 \, a^{3} b^{2} x^{12} + 70 \, a^{4} b x^{9} + 21 \, a^{5} x^{6}\right )} \mathrm {sgn}\left (b x^{3} + a\right ) \]
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Timed out. \[ \int x^5 \left (a^2+2 a b x^3+b^2 x^6\right )^{5/2} \, dx=\int x^5\,{\left (a^2+2\,a\,b\,x^3+b^2\,x^6\right )}^{5/2} \,d x \]
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